Question 733132
f(x)= x^3- 8x^2+ 25x-26


working with the expression...


x^3- 8x^2+ 25x-26=
x^3- 8x^2+12x +13x-26=
x(x^2-8x+12)+13(x-2)=
x(x-2)(x-6)+13(x-2)
(x-2)(x^2-6x+13)

now a=1,b=-6, c=13


*[invoke quadratic "x", 1, -6, 13 ]