Question 752297
If the function has x- intercepts at -5, -3, 0, and 6, it means that f(x) is zero for those values of x.
As a consequence, when the function is factored, it must have all of the following factors:
(x-(-5))=(x+5), which becomes zero when x=-5,
(x-(-3))=(x+3), which becomes zero when x=-3,
(x-0)=x, which becomes zero when x=0, and
(x-6), which becomes zero when x=6.
(It could have other factors too, but it must have those four factors).
So {{{highlight(B)}}}. {{{highlight(f(x)=x(x+5)(x+3)(x-6))}}} is the only option that works.