Question 748069
{{{(log(3,(x)))^2-log(3,(x))=3}}}
{{{let u=log(3,(x))}}}
{{{u^2=(log(3,(x)))^2}}}
u^2-u-3=0
solve by quadratic formula:
u≈-1.303 (reject, log>0)
u≈2.303={{{log(3,(x))}}}
x=3^2.303≈12.51
..
Check:
{{{(log(3,(x)))^2-log(3,(x))}}}=(2.30)^2-2.30≈3