Question 65247
The perimeter of a triangle is 50 centimeters. Side b is 4 centimeters longer than side a. Side c is 9 centimeters shorter than three times the length os side a. find the length of each side.
Let side a be: a
Then side b is: a+4
and side c is: 3a-9
Perimeter is 50 means that if we add the sides, we get 50.
Problem to solve:
(a)+(a+4)+(3a-9)=50
5a-5=50
5a-5+5=50+5
5a=55
5a/5=55/5
a=11
Side a is: a=11 cm
side b is: a+4=11+4=15 cm
side c is: 3a-9=3(11)-9=33-9=24 cm
:
Sanity check:
 If we add all the sides together, do we get 50 cms?
11+15+24=50 ?
50=50 
It appears that we're sane.
Happy Calculating!!!!