Question 638508
y=ax^2+bx+c

(0,10) => c=10

(1,15) => a+b+10=15 or a+b=5

(-1,7) => a-b+10=7 or a-b=-3



adding the two last equations yields 2a=2 so that a=1

and from the second equation a+b=5 we conclude b=4



{{{y=x^2+4x+10}}}


:)