Question 752108
Assuming you want rational numbers, your expression {{{x^2-8x+1}}} is NOT factorable.  


If you do accept irrational numbers, please ask this question again and say that you want or can accept irrational values in the binomial factors.  So far, I am finding ONE OF the constant terms is {{{4-sqrt(15)}}} OR {{{4+sqrt(15)}}} ... and the other....   ...?