Question 752137
Solve each equation by factoring. 

2p2+128=-32p

I will assume 2p2 is 2p^2

Add 32p to each side of the equation.

2p^2 + 128 + 32p = -32p + 32p

Combine like terms:

-32p + 32p = 0

Therefore:

2p^2 + 128 + 32p = 0

Rearrange the above equation.

2p^2 + 32p + 128 = 0

Divide each term by 2

p^2 + 16p + 64 = 0

Factor the trinomial:

(p + 8)^2

Therefore:

(p + 8)(p + 8) = 0

Answer:

p = -8









Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com