Question 752091
I have been trying to turn this word problem into a linear equation for a week now with no success.  Can you help?  

A downtown employee is looking for the best option for parking a car during a 5 day work week.  Garage A offers unlimited parking at a flat rate $150.00 per month. Garage B offers an hourly rate of $5.00 for parking. Which option is best for the employee on a monthly basis?

The employee is parking 160 hours per month.  This is a word problem that I had to come up with on my own make 2 linear equations out of it and then graph it and show where they intercept.  

Any help would be appreciated.  Thank you!


Garage A's charge is $150


Garage B's charge = 5H, with H being amount of hours of parking


5H < 150


H, or hours that'll make garage B's cost less than garage A's should be < {{{150/5}}}, or < {{{30}}}


This means that if a person needs to park for less than 30 hours per month, then garage B will be cheaper.


At 30 hours per month both costs are equal.


Parking for 160 hours DEFINITELY makes garage A the cheaper of the two. You can do the math to see why this is so.


You can graph garage A's linear equation as A(x) = 0x + 150, with x being the amount of monthly-hours of parking


Garage B's equation: B(x) = 5x, with x being the amount of hours of monthly-hours of parking. 


You'll then see where the two equations intersect, which is the point where the two costs are equal.