<PRE><B>Question 752021</B>
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60 degrees does &lt;b&gt;&lt;i&gt;not&lt;/i&gt;&lt;/b&gt; equal the square root of 3.  The sine of 60 degrees is *[tex \LARGE \frac{\sqrt{3}}{2}].   Draw yourself a 30-60-90 right triangle with a hypotenuse that measures 1 unit.  Then the short leg is one-half of the hypotenuse and using the Pythagorean Theorem you can calculate for yourself that the long leg is *[tex \LARGE \frac{\sqrt{3}}{2}].  Since *[tex \LARGE \sin(\varphi)\ =\ \text{\frac{OPP}{HYP}}] and you chose the hypotenuse to have a measure of 1 unit, *[tex \LARGE \sin(\varphi)\ =\ \frac{\sqrt{3}}{2}].   


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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