Question 751986
{{{1/4x + 4y = 2& 3/4}}} and {{{3x + 1/2y = 9& 1/4}}}


Did you really mean this:
{{{(1/4)x + 4y = 2& 3/4}}} and {{{3x + (1/2)y = 9& 1/4}}}
?

Multiply either equation by some number so that the coefficients on either the x or the y are the same, and then subtract one equation from the other equation and solve for the single variable present.  


Alternatively multiply EACH equation by numbers to make the coefficient on either x or y match; and then subtract one equation from the other.  Solve the variable.


Here is one way:
Starting with your second equation,
{{{8*(3x + (1/2)y) = 8*(9& 1/4)}}}
Gives you
{{{24x+4y=74}}} another equivalent equation to your second equation.


So your system could be 
-----------------------------
{{{(1/4)x + 4y = 2& 3/4}}}
{{{24x+4y=74}}}
-----------------------------


See that the coefficients on y in both these are both 4.
Now, subtract the first equation from the second equation, and solve for x.