Question 65226
1- A die was rolled 720 times , what is the probability that the number 4 will be exactly 125 times ?
Prob(X=125)= [720C125](1/6)^125(5/6)^595=0.03466...
Comment: If you are using a TI-83 the problem will cause an 
"overflow" when you try to calculate 720C125.  However, if 
you use binompdf(720,1/6,125) you will get 0.03466...
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2- What is the probability of getting at most three heads in 8 flips of balanced coin ?
P(0<X<3)= binomcdf(8,1/2,3)=0.36328...
Comment: You could also get this answer by calculating P(X=0)
+P(X=1)+P(X=2)+P(X=3)
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Hope this helps.
Cheers,
Stan H.