Question 751612
One number is 4 greater than another number. When three times the smaller number is added to twice the larger one, the result in 43. Find the numbers. 
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If x = y + 5, y must be the smaller number.
3y + 2x = 43
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Substitute for "x" and solve for "y":
3y + 2(y+5) = 43
3y + 2y + 10 = 43
5y = 33
y = 33/6
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Solve for "x":
x = y + 5
x = (33/6) + (30/6)
x = 63/6
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Cheers,
Stan H.
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