Question 751535
Instead of this result, {{{ y=|x-1|+2}}}, use the absolute value portion of function as abs() and then put the tags around the whole function equation:


y=abs(x-1)+2, and with the triple braces,
{{{y=abs(x-1)+2}}}.


Critical point is at {{{x=1}}}.  
at {{{x<1}}}, {{{x-1<0}}} and {{{y=1-x+2}}} or {{{y=-x+3}}}.

At {{{x>=1}}}, {{{y=x-1+2}}}, or {{{y=x+1}}}.


SUMMARY:
You will graph for {{{x<1}}}, {{{y=-x+3}}}
and for {{{x>=1}}}, {{{y=x+1}}}