Question 751569
{{{y=4x-7}}}.......eq.1

{{{y=9x-8}}}........eq.2
____________________________substitute {{{y}}} from eq.1 in eq.2


{{{4x-7=9x-8}}}........eq.2....solve for {{{x}}}

{{{8-7=9x-4x}}}

{{{1=5x}}}

{{{1/5=x}}} or {{{0.2=x}}}

now find {{{y}}}

{{{y=4x-7}}}.......eq.1

{{{y=4(0.2)-7}}}

{{{y=0.8-7}}}

{{{y=-6.2}}}