<PRE><B>Question 751503</B>
equation of the circle whose  tangents are  both x and y axes and the radius at the third quadrant is 2 units.
point of contact of tangent at x axis is (-2,0)
same way point of contact at y axis is (0,-2)
center will lie at (-2,-2)
equation of circle will be (x+2)^2 +(y+2)^2  =2^2

x^2+4+ 4x  +y^2+4+4y =4
writing in standard  form of circle 
equation of circle will be 
x^2+y^2 +4x+ 4y  +4 =0


ANSWER   x^2+y^2 +4x+ 4y  +4 =0


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