Question 751407
x = -2 or x = -4i or x = 4i


x + 2 = 0 or x + 4i = 0 or x - 4i = 0 


(x + 2)(x + 4i)(x - 4i) = 0 


(x + 2)(x^2 - (4i)^2) = 0 


(x + 2)(x^2 - 16i^2) = 0 


(x + 2)(x^2 - 16(-1)) = 0 


(x + 2)(x^2 + 16) = 0 


x(x^2 + 16) + 2(x^2 + 16) = 0 


x^3 + 16x + 2x^2 + 32 = 0 


x^3 + 2x^2 + 16x + 32 = 0 


Final Answer: <font color="red">y = x^3 + 2x^2 + 16x + 32</font>