<PRE><B>Question 751358</B>
{{{2a^2-9a-18}}}


These problems take a bit of trial and error. 

{{{(2a+2)(a-9)= 2a^2-16a-18}}}  I got the first and last term but we need the middle term to work. 


The 2 has just the two factors, 2 and 1, but 18 has these pairs,(18,1)(9,2)(6,3) along with the choice of where the negative sign goes. 

Turns out this is the correct result -

{{{(2a+3)(a-6)}}}

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