Question 751248
In a 45°-45°-90° triangle, the length of the hypotenuse is equal to {{{sqrt(2)}}} times the length of the leg.
If hypotenuse = 12 feet, then the length of each leg is {{{12/sqrt(2)}}} ft = {{{6sqrt(2)}}} ft.

Perimeter = 12 + {{{2(6sqrt(2))}}} ft = {{{highlight(12 + 12sqrt(2))}}} ft
Area = Square the length of the leg then divide by 2
     = {{{((6sqrt(2))^2)/2}}} sq ft = {{{highlight(36)}}} sq ft