Question 751222
3x^2+5x=42


3x^2+5x-42 = 0


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(5)+-sqrt((5)^2-4(3)(-42)))/(2(3))}}} Plug in {{{a = 3}}}, {{{b = 5}}}, {{{c = -42}}}


{{{x = (-5+-sqrt(25-(-504)))/(6)}}}


{{{x = (-5+-sqrt(25+504))/(6)}}}


{{{x = (-5+-sqrt(529))/6}}}


{{{x = (-5+sqrt(529))/6}}} or {{{x = (-5-sqrt(529))/6}}}


{{{x = (-5+23)/6}}} or {{{x = (-5-23)/6}}}


{{{x = 18/6}}} or {{{x = -28/6}}}


{{{x = 3}}} or {{{x = -14/3}}}


The two solutions are {{{x = 3}}} or {{{x = -14/3}}}