Question 65114
graph f(x)=xsquared-1
If you're supposed to use transformations to graph this, it is the graph of {{{f(x)=x^2}}} shifted down one unit.
If you've never heard of that before, this is a parabola.  We can plot a few points to find it.
The y-intercept is where x=0.
{{{f(0)=(0)^2-1}}}
{{{f(0)=-1}}}
Plot (0,-1)
The x intercept is where y=0
{{{0=x^2-1}}}
{{{0=(x+1)(x-1)}}}
x+1=0 and x-1=0
x+1-1=0-1 and x-1+1=0+1
x=-1 and x=1
Plot (-1,0) and (1,0)
The vertex is the turning point of the parabola, if you have x-intercepts, it's x-coordinate is half-way between the two intercepts.
x={{{(-1+1)/2=0}}}  we already have that point in the y-intercept, but that's not always going to happen.
This is what your graph ends up looking like:
{{{graph(300,200,-10,10,-10,10,x^2-1)}}}
Happy Calculating!!!