Question 712556
For convenience we write:   |x+3|=|x+2|+|x-5|


We'll solve by checking the following cases:

+ + +
+ + -
+ - +
+ - -




+++
x+3=x+2+x-5
x=6 (yes-solution)


++-
x+3=x+2-(x-5)
x=4 (yes-solution)


+-+
x+3=-(x+2)+x-5
x=-10 (no-not a solution)


+--
x+3=-(x+2)-(x-5)
x=0 (no-not a solution)


solution {4, 6}


:)