Question 750964
lne^(x^2+3x-4)=ln5
log of base raised to exponent=exponent
(x^2+3x-4)=ln5
(x^2+3x-4)=ln(5)≈1.6094
x^2+3x-4-1.6094=0
x^2+3x-5.6094=0
use quadratic formula to solve for x
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=3, c=5.6094
x≈1.3035
or
x≈-4.3035