Question 750580
{{{w^3 + 7w^2 + 4w + 28}}}

First guess is try to do something with the factors of 7.

{{{w^3+4w+7w^2+28}}}
{{{w^3+4w+7(w^2+4)}}}


See some w factors in the other two terms
{{{w(w^2+4)+7(w^2+4)}}}


Notice two summed expressions each have a factor of w^2+4 distributed.  We can reverse that distribution.
{{{(w^2+4)(w+7)}}}


And that is the fully factored form.  {{{highlight((w^2+4)(w+7))}}}