Question 750429
The volume of the added balls to the cylinder is {{{pi*12^2*8}}} {{{cm^3}}}.


1 ball has volume of {{{(4/3)*pi*3^3}}} {{{cm^3}}}.


The simplest question now to ask is, how many of these 1-ball volumes are in the volume difference found in the cylinder?  {{{(pi*12^2*8)/((4/3)*pi*3^3)}}} is how many balls.