Question 750549

 find the first {{{5}}} terms of:  

{{{ an=(7n!)/(n+2) }}}......if {{{n=1}}}


{{{ a[1]=(7*1)/(1+2) }}}


{{{ a[1]=7/3 }}}.....first term


{{{ a[n]=(7n!)/(n+2) }}}......if {{{n=2}}}


{{{ a[2]=(7*2*1)/(2+2) }}}


{{{ a[2]=14/4 }}}


{{{ a[2]=7/2 }}}.....second  term



{{{ a[n]=(7n!)/(n+2) }}}......if {{{n=3}}}


{{{ a[3]=(7*3*2*1)/(3+2) }}}


{{{ a[3]=42/5 }}}.....third  term



{{{ a[n]=(7n!)/(n+2) }}}......if {{{n=4}}}


{{{ a[4]=(7*4*3*2*1)/(4+2) }}}


{{{ a[4]=168/6 }}}


{{{ a[4]=28 }}}.....fourth  term



{{{ a[n]=(7n!)/(n+2) }}}......if {{{n=5}}}


{{{ a[5]=(7*5*4*3*2*1)/(5+2) }}}


{{{ a[5]=840/7 }}}


{{{ a[5]=120 }}}.....fifth  term



{..{{{7/3 }}},{{{7/2 }}},{{{42/5 }}},{{{28 }}},{{{120 }}}..}