Question 750541
The greatest area a fence can surround in a rectangle is in h shape of a square. Let me offer a reason why.

If one side is a tiny bit longer, the adjacent side is shorter by the same amount.

(X-Y)(X+Y)=X^2-Y^2 so the maximum area is when Y= 0.

In your case, we can't have sqr(102) as a side, so with two sides adding to 51, I'll say 25x26 are the dimensions.