Question 750448
3(t+1)=3(2t-3)
3t+3=6t-9
3t-6t=-9-3
-3t=-12
t=-12/-3
t=4 bulbs ans.
Proof:
3(4+1)=3(2*4-3)
3*5=3(8-3)
15=3*5
15=15