Question 750512
Simplify "v" to the 6th power multiplied by "v" to the 3rd power, then "v" to the 6th power.
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{{{v^6*v^3*v^6 = v^(6+3+6) = v^15}}}
Multiplying --> adding exponents.
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Would the v6's cancel each other out?
No, they're added.  If one was -6, then they would "cancel."  6 + (-6) = 0