Question 750474
Give the focus, directrix, and axis of symmetry for the parabola X^2=1/8y
parabola opens upward:
Its basic form of equation: x^2=4py
vertex=(0,0)
axis of symmetry: x=0 or y-axis
4p=1/8
p=1/32
focus: (0,1/32) (p-distance from center to focus on the axis of symmetry)
directrix: y=-1/32 (p-distance from center to directrix on the axis of symmetry)