Question 65159
To easily determine the vertex we have to bring the function to the following form: 
{{{y = a(x-h)^2+k}}} and the vertex is: (h,k)
To do that, we basically need to complete the square
{{{x^2-6x = x^2 - 2*3x + 9 - 9 = (x-3)^2 -9}}}
Therefore, our new form is:
{{{y = (x-2)^2 -9}}} 
We can now spot the vertex: (2,9)


To determine the intercepts, we simply have to solve the equation: 
{{{x^2-6x =0}}}
Solutions: {0, 6} - these are the x-intercepts


Hope it helped,
Cristiana