Question 750266
{{{1x/(2*(1/2)) +3y/(3*(1/3)) = 2}}}= {{{x+3y=2}}}
{{{1x/(3*(1/2)) +1y/(2*(1/3)) = 13 / 6}}}={{{(2/3)x+(3/2)y=13/6}}}---> multiply with 6

1. {{{x+3y=2}}}
2. {{{4x+9y=13}}}

well, that's clear now to solve it.
Cheers