Question 750174
x^2 + (x+2)^2 = (2x-2)^2  is the set up for this equation.

x^2+x^2+4x+4= 4x^2-8x+4   expanded both sides

2x^2+4x+4=4x^2-8x+4

-2x^2+12x=0

2x^2-12x=0

x^2-6x=0

x=0 or x=6

6, 8, 10 are the sides