Question 750150
It appears to be factorable.  Multiplying two binomials gives you initially four terms, and often you will be able to combine two of the terms into one like-term.


Would this factorization work?  
{{{(tx-2)(x+3)}}}
{{{highlight(tx^2-2x+3tx-6)}}}
?


Would this factorization work?
{{{(tx+3)(x-2)}}}
{{{highlight(tx^2+3x-2tx-6)}}}
?


Examine those very carefully and you see that one of them matches your equation's left member and one of them does not match.  Pick the one that works and continue to solve for x.