Question 750164
Your use of grouping at least makes clear what you start with.


{{{4*sqrt(2x+7)-5=7}}}
{{{4*sqrt(2x+7)=7+5=12}}}
{{{sqrt(2x+7)=12/4=3}}}
{{{(sqrt(2x+7))^2=9}}}
{{{2x+7=9}}}
{{{2x=9-7=2}}}
{{{x=1}}}  DONE