Question 750081
How do i solve
(x+1)/3 = 2/(2x-1)

I know it has to be something like:
(x+1)(2x-1)=3x2 Use * for multiply.  x is taken
(x+1)(2x-1)=6
-------
2x^2 + x - 1 = 5
2x^2 + x - 6 = 0
*[invoke solve_quadratic_equation 2,1,-6]