Question 749834

how to mix a 10%solution and a 30% solution to get 1000ml of a 12% solution?


Let amount of milliliters of 10% solution to be added, be T
Then: .1T + .3(1,000 – T) = .12(1,000)
.1T + 300 - .3T = 120
.1T - .3T = 120 – 300 
- .2T = - 180


T, or amount of 10% solution to be added = {{{(- 180)/- .2}}}, or {{{highlight_green(900)}}} mL


Amount of 30% solution to be added = {{{highlight_green(100)}}} (1,000 – 900) mL