Question 65130
Let the two consecutive numbers be x and (x+1)
{{{x*(x+1) = 182}}} Simplify.
{{{x^2 + x = 182}}} Subtract 182 from both sides.
{{{x^2 + x - 182 = 0}}} Solve this quadratic equation by factoring.
{{{(x + 14)(x - 13) = 0}}} Apply yhe zero product principle.
{{{x + 14 = 0}}} and {{{x - 13 = 0}}}
If {{{x + 14 = 0}}} then {{{x = -14}}} This is one solution!
{{{If x - 13 = 0}}} then {{{x = 13}}} This the other solution!.
{{{x = 13}}} and {{{x+1 = 14}}}
{{{x = -14}}} and {{{x+1 = -13}}}
The two numbers are 13 and 14 and the other two are -14 and -13