Question 65131
Let the two numbers be x and y.
1) x+y = 28  Rewrite this as: x = 28-y and substitute for x in equation 2).

2) {{{x*y = 96}}}
2a) {{{(28-y)*y = 96}}} Simplify this:
{{{28y - y^2 = 96}}} Now add {{{y^2}}} to both sides of the equation.
{{{28y = y^2 + 96}}} Subtract 28y from both sides.
{{{y^2 - 28y + 96 = 0}}} Solve this quadratic equation by factoring.
{{{(y - 4)(y - 24) = 0}}} Apply the zero product principle.
{{{y - 4 = 0}}} and {{{y - 24 = 0}}}
If {{{y - 4 = 0}}} then {{{y = 4}}}
If {{{y - 24 = 0}}} then {{{y = 24}}}
The two numbers are: 4 and 24.