Question 749617
Given, shown in abbreviated form: 2tan*sin+2cos-csc


2(sin/cos*)sin+2*cos-1/sin
2(sin/cos)*sin*(sin/sin)+2*cos*(cos/cos)*(sin/sin)-(1/sin)*(cos/cos)
(2sin^3+2(cos^2)sin-cos)/(sin*cos)
(2sin*(sin^2+cos^2)-cos)/(sin*cos)
Notice the identity expression sin^2+cos^2=1;
2sin*(1-cos)/(sin*cos)
.
2/cos-2cos/cos
{{{highlight(2sec-2)}}}  or {{{highlight(2(sec-1))}}}


For some unknown reason, rendering was not working, so I removed the triple brackets tags on most of the steps.  I know this makes reading more difficult.