Question 749529
D=RT
332=R*3
R=332/3
R=110.67 TOTAL SPEED OF THE 2 CARS.
X+X+36=110.67
2X=110.67-36
2X=74.67
X=74.67/2
X=37.335 MPH FOR THE SLOWER CAR.
37.335+36=73.335 MPH FOR THE FASTER CAR.
PROOF:
332=(37.335+73.335)*3
332=110.67*3
332=332