Question 64780
2x^2-x-3    3x^2-11x-20
--------- X ------------- =
3x^2+7x+4    4x^2-9
:
:
{{{(2x^2 - x - 3)/(3x^2 + 7x + 4)}}} * {{{(3x^2 - 11x - 20)/(4x^2 - 9)}}}
:
All of these will factor, do that first:
:
{{{((2x-3)(x+1))/((3x+4)(x+1))}}} * {{{((3x+4)(x-5))/((2x-3)(2x+3))}}}
:
Observe that the following will cancel:(2x-3),(x+1),(3x+4), eliminates
the first faction (actually becomes 1), leaves us with:
:
{{{(x-5)/(2x+3)}}}
:
You can see no multiplying actually took place. Could you follow this OK?