Question 749524
How do you solve {{{(22x^8y^2z^5/14x^3z)(35x^4y^3z/32x^2yz^8)}}}
---------------
You don't solve it.  When something is solved, you get x = ..... or y = ... something.
This is to be simplified.
{{{(22x^8y^2z^5/14x^3z)(35x^4y^3z/32x^2yz^8)}}}
Cancel things, one at a time or in groups.
= {{{(11x^5y^2z^5/7z)(35x^4y^3z/32x^2yz^8)}}}
= {{{(11x^5y^2)(5x^4y^3z/32x^2yz^4)}}}
= {{{(11x^5y^2)(5x^2y^2/32z^3)}}}
= {{{(55x^7y^4)(1/32z^3)}}}
= {{{55x^7y^4/(32z^3)}}}
--------------
My final answer was 770x^7y^4/448z^3
Your answer can be reduced further
770x^7y^4/448z^3
= 110x^7y^4/64z^3
= 55x^7y^4/32z^3 the same