Question 749350
We look for a pair of numbers that "add" to 7 and multiply to -8 and discover -1 and 8


4x^2+7x-2=

4x^2+(8x-x)-2=


4x^2+8x-x-2=


(4x^2+8x)-(x+2)=


4x(x+2)-1(x+2)


(4x-1)(x+2)




:)