Question 749255
Try putting each equation into the same form, you choose, either standard form or general form.  The second one is already in standard form.  Try then working with first the first equation.


{{{4 - 2x = (1/2)y}}}______assuming you meant the {{{1/2}}} to be grouped separately from the y
multiply both sides by 2
{{{8-4x=y}}}
{{{-4x-y=-8}}}
{{{4x+y=8}}}


Your system is then this:
{4x+y=8}
{4x+6y=-6}


Subtract one equation from the other equation using the fact that this will eliminate the 4x, allowing you to quickly find the value for y.  Now using what you found for y, find x.


To began that process,
{{{4x+y-(4x+6y)=8-(-6)}}}
{{{4x+y-4x-6y=8+6}}}
{{{4x-4x+y-6y=14}}}
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