Question 749235
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*[tex \LARGE x\ +\ y\ =\ 1]


*[tex \LARGE xy =\ -1]


*[tex \LARGE y\ =\ 1\ -\ x]


So


*[tex \LARGE x(1\ -\ x)\ =\ -1]


*[tex \LARGE x^2\ -\ x\ -\ 1\ =\ 0]


Use the quadratic formula.  The two roots will be your two numbers.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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