Question 65070
There are an infinite number of points on a line.  The easiest one to find in this case is the y-intercept.  Let x=0 and solve for y.
What is a point that goes through the line y=2/3x+3
y=(2/3)(0)+3
y=0+3
y=3
The point (x,y)=(0,3) is on the line.
You can let x be anything you want, but if you want integers for y, let x be things divisible by 3.
When x=-3
y=(2/3)(-3)+3
y=-6/3+3
y=-2+3
y=1
The point (x,y)=(-3,1) is also on the line.
Why don't you find the point when x=3, and tell me what you get?
Happy Calculating!!!