Question 749054
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To begin with, your terminology is incorrect.  Intercepts are points and points (in *[tex \LARGE \mathbb{R}^2]) are specified using ordered pairs.  So giving a number and calling it an intercept is incorrect.  Presuming you mean that the *[tex \LARGE x]-coordinate of the *[tex \LARGE x]-intercept is 12 and the *[tex \LARGE y]-coordinate of the *[tex \LARGE y]-intercept is 14, then you have been given two points on the desired line, namely *[tex \LARGE (12,0)] and *[tex \LARGE (0,14)].


Use the two-point form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Once you have made the substitutions of the coordinates, simplify and solve for *[tex \LARGE y] in terms of everything else.  That is to say, put your equation in the form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ mx\ +\ b]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \