<PRE><B>Question 749058</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ \frac{7}{x\,+\,1}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(a)\ =\ \frac{7}{a\,+\,1}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(a\,+\,h)\ =\ \frac{7}{a\,+\,h\,+\,1}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{f(a\,+\,h)\ -\ f(a)}{h}\ =\ \frac{\frac{7}{a\,+\,h\,+\,1}\ -\ \frac{7}{a\,+\,1}}{h}]


All that is left is to simplify.  Hint:  Leave the common denominator of the two fractions in the numerator as a product of a binomial and a trinomial.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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