Question 748985


{{{6x^3y^3z+12x^2y^2z^3}}}...
factor for {{{6}}} and {{{12}}} is {{{6}}},
factor for {{{x^3}}} and {{{x^2}}} is {{{x^2}}}
factor for {{{y^3}}} and {{{y^2}}} is {{{y^2}}}
factor for {{{z}}} and {{{z^3}}} is {{{z}}}

so factor out {{{6x^2y^2z}}}

{{{6x^2y^2z(xy+2z^2)}}}