Question 748833
what is the simplest form of:
{{{((x+3))/((x^3-x^2-6x))}}}
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{{{((x^2-9))/((x^2+x-12))}}}
:
Remember when you divide fractions, invert the dividing fraction and Multiply
{{{((x+3))/((x^3-x^2-6x))}}} * {{{((x^2+x-12))/((x^2-9))}}}
:
Factor as much as we can
{{{((x+3))/(x(x^2-x-6))}}} * {{{((x+4)(x-3))/((x-3)(x+3))}}}
: 
the first denominator can be factored again
{{{((x+3))/(x(x-3)(x+2))}}} * {{{((x+4)(x-3))/((x-3)(x+3))}}}
:
Cancel x+3 and x-3, in the 2nd denominator
{{{1/(x(x-3)(x+2))}}} * (x+4) = {{{((x+4))/(x(x-3)(x+2))}}}; about all you can do with it. 
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:
It's not an equation, expressions are what they are